A video illustrating the previous article .
The red is a bit flashy, sorry for that…
Juil 062014
A video illustrating the previous article .
The red is a bit flashy, sorry for that…
In a previous article, we had used a 74HC595 to control a ULN2803.
This enabled us to deal with 8 LED’s.
Lets now cascade two 74HC595 to deal with 16 LED’s.
To do this, we will use the serial output of 74HC595 #1 to the serial input of 74HC595 #2.
Here below the schema.
Here below the arduino sketch.
Note that we use two arrays, and that we go up and down in each array.
//the pins we are using int latchPin = 2; int clockPin = 3; int dataPin = 4; byte dataArrayA[9]; byte dataArrayB[9]; void setup() { //set all the pins used to talk to the chip //as output pins so we can write to them pinMode(latchPin, OUTPUT); pinMode(clockPin, OUTPUT); pinMode(dataPin, OUTPUT); dataArrayA[0] = 0xFF; //11111111 dataArrayA[1] = 0xFE; //11111110 dataArrayA[2] = 0xFC; //11111100 dataArrayA[3] = 0xF8; //11111000 dataArrayA[4] = 0xF0; //11110000 dataArrayA[5] = 0xE0; //11100000 dataArrayA[6] = 0xC0; //11000000 dataArrayA[7] = 0x80; //10000000 dataArrayA[8] = 0x00; //00000000 dataArrayB[8] = 0xFF; //11111111 dataArrayB[7] = 0xFE; //11111110 dataArrayB[6] = 0xFC; //11111100 dataArrayB[5] = 0xF8; //11111000 dataArrayB[4] = 0xF0; //11110000 dataArrayB[3] = 0xE0; //11100000 dataArrayB[2] = 0xC0; //11000000 dataArrayB[1] = 0x80; //10000000 dataArrayB[0] = 0x00; //00000000 } void loop() { for (int i = 0; i < 9; i++) { digitalWrite(latchPin, LOW); shiftOut(dataPin, clockPin, MSBFIRST, dataArrayA[i]); shiftOut(dataPin, clockPin, MSBFIRST, dataArrayB[i]); digitalWrite(latchPin, HIGH); delay(100); } for (int i = 8; i >= 0; i--) { digitalWrite(latchPin, LOW); shiftOut(dataPin, clockPin, MSBFIRST, dataArrayA[i]); shiftOut(dataPin, clockPin, MSBFIRST, dataArrayB[i]); digitalWrite(latchPin, HIGH); delay(100); } }